Arm® A32/T32 Instruction Set Architecture: Armv8, for Armv8-A architecture profile Documentation

SDIV

Signed Divide divides a 32-bit signed integer register value by a 32-bit signed integer register value, and writes the result to the destination register. The condition flags are not affected.

It has encodings from the following instruction sets: A32 ( A1 ) and T32 ( T1 ) .

A1

d = UInt(Rd);  n = UInt(Rn);  m = UInt(Rm);  a = UInt(Ra);
if d == 15 || n == 15 || m == 15 || a != 15 then UNPREDICTABLE;

CONSTRAINED UNPREDICTABLE behavior

If Ra != '1111', then one of the following behaviors must occur:

• The instruction is undefined.
• The instruction executes as NOP.
• The instruction executes as described, with no change to its behavior and no additional side effects.
• The instruction executes as described, and the register specified by Ra becomes unknown.

T1

d = UInt(Rd);  n = UInt(Rn);  m = UInt(Rm);  a = UInt(Ra);
if d == 15 || n == 15 || m == 15 || a != 15 then UNPREDICTABLE; // Armv8-A removes UNPREDICTABLE for R13

CONSTRAINED UNPREDICTABLE behavior

If Ra != '1111', then one of the following behaviors must occur:

• The instruction is undefined.
• The instruction executes as NOP.
• The instruction executes as described, with no change to its behavior and no additional side effects.
• The instruction executes as described, and the register specified by Ra becomes unknown.

For more information about the constrained unpredictable behavior of this instruction, see Architectural Constraints on UNPREDICTABLE behaviors.

Assembler Symbols

Overflow

If the signed integer division 0x80000000 / 0xFFFFFFFF is performed, the pseudocode produces the intermediate integer result +2³¹, that overflows the 32-bit signed integer range. No indication of this overflow case is produced, and the 32-bit result written to <Rd> must be the bottom 32 bits of the binary representation of +2³¹. So the result of the division is 0x80000000.

if ConditionPassed() then
    EncodingSpecificOperations();
    if SInt(R[m]) == 0 then
        result = 0;
    else
        result = RoundTowardsZero(Real(SInt(R[n])) / Real(SInt(R[m])));
    R[d] = result<31:0>;